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fix: if username is not present in SAS9, derive it with full name

This commit is contained in:
Saad Jutt
2021-09-06 12:42:26 +05:00
parent e4956cc1d4
commit 3ccd35a4e2

View File

@@ -172,10 +172,22 @@ export class AuthManager {
}) })
} }
private extractUserName = (response: any): string => private extractUserName = (response: any): string => {
this.serverType === 'SASVIYA' switch (this.serverType) {
? response?.id case ServerType.SasViya:
: response?.match(/"title":"Log Off [0-1a-zA-Z]*"/)?.[0].slice(17, -1) return response?.id
case ServerType.Sas9:
const matched = response?.match(/"title":"Log Off [0-1a-zA-Z ]*"/)
const username = matched?.[0].slice(17, -1)
if (username.length === 6) return username
return username
.split(' ')
.map((name: string) => name.slice(0, 3).toLowerCase())
.join('')
}
}
private getLoginForm(response: any) { private getLoginForm(response: any) {
const pattern: RegExp = /<form.+action="(.*Logon[^"]*).*>/ const pattern: RegExp = /<form.+action="(.*Logon[^"]*).*>/